5.
	a)
epsikj * epsjlm =
(eiej	eiel	eiem)
(ekej	ekel	ekem)
(ejej	ejel	ejem)
=
(dij	dil	dim)
(dkl	dkl	dkm)
(djj	djl	djm)
=dij dkl djm + dil dkm djj + dim dkj djl - dim dkl djj - dil dkj djm - dkm djl dij
Durch einsteinsche Summenkonvention folgt, dass nur sumanden, die doppelte indizes beinhalten summiert werden.
=dildkmdjj - dimdkldjj
=dildkm - dimdkl

	a) alternativ
sume(j){epsikj * epsjlm}
=sum(j){i(kxj)*j(lxm)}
	(=sum(j){(lxk)*j*j*(mxi)})
=sum(j){(ixk)*j*j*(lxm)}
=(ixk)*(lxm)
=(i2k3-i3k2 +i3k1-i1k3 +i1k2-i2k1)*
(l2m3-l3m2 +l3m1-l1m3 +l1m2-l2m1)
=i2k3l2m3-i2k3l3m2+i2k3l3m1-i2k3l1m3+i2k3l1m2-i2k3l2m1
-i3k2l2m3+l3m2i3k2-l3m1i3k2+l1m3i3k2-l1m2i3k2+l2m1i3k2
+l2m3i3k1-l3m2i3k1+l3m1i3k1-l1m3i3k1+l1m2i3k1-l2m1i3k1
-l2m3i1k3+l3m2i1k3-l3m1i1k3+l1m3i1k3-l1m2i1k3+l2m1i1k3
+l2m3i1k2-l3m2i1k2+l3m1i1k2-l1m3i1k2+l1m2i1k2-l2m1i1k2
-l2m3i2k1+l3m2i2k1-l3m1i2k1+l1m3i2k1-l1m2i2k1+l2m1i2k1

=Dli2Dmk3-Dmi2Dlk3+Dlk3m1i2-Dmk3l1i2+Dmi2l1k3-Dli2m1k3
-Dlk2Dmi3+Dmk2Dli3-Dli3m1k2+Dmi3l1k2-Dmk2l1i3+Dlk2m1i3
+Dmi3l2k1-Dli3m2k1+Dmk1Dli3-Dlk1Dmi3+Dlk1m2i3-Dmk1l2i3
-Dmk3l2i1+Dlk3m2i1-Dmi1Dlk3+Dli1Dmk3-Dli1m2k3+Dmi1l2k3
+Dlk2m3i1-Dmk2l3i1+Dmi1l3k2-Dli1m3k2+Dli1Dmk2-Dmi1Dlk2
-Dli2m3k1+Dmi2l3k1-Dmk1l3i2+Dlk1m3i2-Dlk1Dmi2+Dmk1Dli2

=Dli1Dmk2+Dli1Dmk3+Dli2Dmk1+Dli2Dmk3+Dli3Dmk1+Dli3Dmk2
-Dmi1Dlk2-Dmi1Dlk3-Dmi2Dlk1-Dmi2Dlk3-Dmi3Dlk1-Dmi3Dlk2
+Dlk1m3i2+Dlk1m2i3+Dlk2m3i1+Dlk2m1i3+Dlk3m2i1+Dlk3m1i2
-Dmk1l3i2-Dmk1l2i3-Dmk2l3i1-Dmk2l1i3-Dmk3l2i1-Dmk3l1i2
+Dmi1l3k2+Dmi1l2k3+Dmi2l3k1+Dmi2l1k3+Dmi3l2k1+Dmi3l1k2
-Dli1m3k2-Dli1m2k3-Dli2m3k1-Dli2m1k3-Dli3m2k1-Dli3m1k2

=DliDmk-DmiDlk

+Dlk1m3i2+Dlk1m2i3+Dlk2m3i1+Dlk2m1i3+Dlk3m2i1+Dlk3m1i2
+Dmi1l3k2+Dmi1l2k3+Dmi2l3k1+Dmi2l1k3+Dmi3l2k1+Dmi3l1k2
-Dmk1l3i2-Dmk1l2i3-Dmk2l3i1-Dmk2l1i3-Dmk3l2i1-Dmk3l1i2
-Dli1m3k2-Dli1m2k3-Dli2m3k1-Dli2m1k3-Dli3m2k1-Dli3m1k2

=DliDmk-DmiDlk

+Dlk*|mxi|
+Dmi*|lxk|
-Dmk*|lxi|
-Dli*|mxk|

falls l=k=m=i, dann 0+0+0-0
falls l=k=m\=i, dann 1+0-1-0
falls k=l=i\=m, dann 1+0-0-1
falls i=k=m\=l, dann 0+1-1-0
falls m=l=i\=k, dann 0+1-0-1
falls l=k und m=i mit l\=m, dann 0+0-0-0
falls m=k und l=i mit l\=k, dann 0+0-0-0
falls m\=k\=i\=l 0+0-0-0

	b)blatt... tipp: +-abc
	c)
